Average pace, vs, average speed, harmonic mean example,

This is my hardest math video to make so far. You can also see the solutions @1:50 ,

harmonic mean, San Francisco Marathon 2017, running vlog,

average of 6 mph and 4 mph is NOT 5 mph,

Filmed on GoPro4 session, & iPhone6,

HARMONIC MEAN,

classic tricky question,

math for fun,

average speed,

average pace,

how to find the harmonic mean,

San Francisco Marathon 2017,

Run & Math,

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google parker pen,

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source

Go sleep dude kkkk

Where did you get that awesome pen? =D

the average speed is 40/9 mph

Based on length or time? Length based it would be 11min/mile. Time whise it would be I don't know. I don't want to calculate that right now

isn't the lowest common multiple of 12 and 8,24?

But you don't have to take my word for it..

"I ain't doing this again, FUCK!" ?????

Here's more about harmonic mean: https://en.wikipedia.org/wiki/Harmonic_mean. Here are some other means with trapezoids: http://jwilson.coe.uga.edu/EMT668/EMAT6680.2000/Umberger/EMAT6690smu/Essay3smu/Essay3smu.html

It shows that the Harmonic Mean < Geometric Mean < Heronian Mean < Arithmetic Mean < Centroidal Mean < Root-Mean-Square < Contraharmonic Mean.

Filming yourself while running a marathon: hardcore. Asking a math question while running a marathon: kinda crazy. : )

Good shit man! What a beast 🙂

Can't wait to see some hardcore students getting triggered over the fact that a math teacher said "fuck" in his video

Intuitively speaking assuming it's a step function which goes from 6 to 4, you will spend more time in 4 building up the area beneath the curve AKA the distance traveled. As such a perfect way to model this is weighing the smaller number which is why the reciprocal is useful beyond simply giving the correct units it's derivative is descending 1/4<1/6. Of course this all just coincides with the fact the units match up and the formulas match up

I think it's 4.8 mph

Congrats on the marathon! Now back to maths 🙂

Why do you do both mathematics

andathletic/sports stuff in your life instead of just one xor the other? Is itrequiredto do both instead of just one xor the other? Is one abadperson if you only do one xor the other and not both? This is a rather odd obsessional topic of mine and I want to hear opinions of various sorts about this due to the strange tension in my head and gut that it seems to bring up."好累!" lol

Video is

tauminutes longNote: for all the ppl that are gonna go like ''thats not actually tau minutes long in hexadecimal its actually blah blah'' just let people enjoy things

Can you solve the calculus south korean college admission math test type B?

guy seriously thanks for making these videos

5:11 The lowest common multiple of 12 and 8 is 24, not 48.

Not that it matters much, you only need some common multiple of 12 and 8.

you should have did a voice over in the first part of the video instead of talking when you're running lol

Will you make a tutorial for differntation / integration

I will learn it next year but I think you can teach very well !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

4.8 miles/hour

Yet you didn't have an easy solution to the marathon.

I have one, you deserve a Pizza after that run to regain all the lost calories.

So basically: 1/(1/4+1/6)

Marathon and maths all in one video?!

That's Hardcore. :]

Fuck yeah, SF marathon!

small error: lowest common denominator of 12 and 8 is 24, not 48. The mistake doesn't effect your answer, but calling 48 the lowest common denominator might confuse some people.

mathematics and physical excercise, something that most people don't do.. impressive.

Can you share a way to quickly compute the zeros of (x-1)(x-2)(x-3)(x-4)+1. I feel like there should be an easy way or trick to do this without multiplying everything out, thanks

By the way, Lcm of 12 and 8 is 24 ?

Amazing video though, iIreally liked the style of this one ????

Where did you get the Google notepad?

Francisco marathon , FUCK YEAH ?

Let's say that a marathon is x miles.

for the first x/2 miles you travel at 10 min/mile (faster)

for the second x/2 miles you travel at 12 min/mile (slower)

For the sake of simplicity, let x =2. So for the first mile it takes 10 minutes and for the second mile it takes 12 minutes. So your average speed would be ( 1/10 ) miles/ minutes * (10/22) + ( 1/12 ) miles/minute * (12/22) = 2/22 miles/minute

So that means the average pace would be 22/2 minutes/ mile

WHY ARE YOU RUNNING MARATHONS, YOU SHOULD BE RUNNING MATHATHONS!!!!

maths everywhere hahaha…

keep up the good work man ??

1. Great job running a 4:41:00 marathon while talking and holding a go pro stick at the same time!

2. LCD in your avg speed calculation should be 24, not 48, no big deal 🙂

3. Aren't we runners genius for coming up with an invariant for measuring our pace…it withstands the nasty harmonic mean calculation!

3.5 My PR = 3:40:00 at '15 NYC marathon 🙂

You've changed the title of this video at least 5 times.

Hey sick Video! You deserve more attention than you get! Anyways I'm a YouTuber currently on 13k subs and I'm looking for promising YouTubers like you to help grow through my shout out series. You could gain alot of subscribers from it easily! If you're interested you just have to follow a couple of easy rules. 1. Subscribe to me and turn notifications on and 2. Stay active on my channel (liking and commenting on my videos so I notice you). That's all! I'd love to see you over on my channel – make a new YouTube friend! Keep producing good content!!!?

d = s * t == > d / s = t

total distance = d1 + d2

average rate = ( d1 + d2 ) / [ (d1 / s1) + (d2 / s2) ]

average rate = (d1 + d2 ) * s1 * s2 / [ d1*s2 + d2 * s1 ]

average rate = s1 * s2 / [ ( d1 / (d1 + d2 ) )*s2 + ( d2 / ( d1 + d2 ) )*s1 ]

Now if d1 = d2 we get :

average rate = s1 * s2 / [ ( 1 / 2 )* s2 + ( 1 / 2 ) * s1 ]

average rate = 2 * s1 * s2 / ( s1 + s2 ) This is called the harmonic mean.

Isn't it?

5:18 The lcm is 24, not 48

sir plzz. solve this:-integration of e^x/(1+x)^2

11 minutes per mile?

I just averaged the reciprocals of the two speeds and took the reciprocal of that. Same answer, 4.8.

Professor in good condition