CAT 2006 : If a/b=1/3 , b/c= 2, c/d=1/2, d/e= 3 and e/f=1/4, then what is the value ofabc/def ?
(1) 3/8 (2) 27/8 (3) 3/4 (4) 27/4 (5) 1/4
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Sir…pls do long videos with more questions
Your solutions is very beautiful.
My solution is more complicated :
a*b*c/d*e*f = [1/2]*(a*b)/(e*f) = [1/2]*(a*b*d)/(d*e*f) = [3/2]*(a*b)/(d*f) = [3/2] (a*b*e)/(d*e*f)
= [3/8] * (a*b*d)/(d^2*e) = [9/8] * (a*b)/d^2 = [9/8] (a*b*c^2)/(c^2*d^2) = [9/32] (a*b)/c^2
= [9/32] * a/c * b/c = [18/32] * a/c = [18/32]*(a*b)/(b*c) = 18/32*1/3*2 = 36/96 = 3/8….