IIT JEE Advanced Rank Booster Problem for students AIR 1 – 1000.
Here is solved problem 3 on complex number. the problem is based on rotation of complex number, triangle and understanding of Argand plane.
Here is the Problem:
The affixes of a triangle in Argand plane are A(2iω + 1), B(1 – 2ω) and C (1-2i) where ω = 𝑒^𝑖(2𝜋/3) . Then triangle ABC is
(A) Acute, ∠A = 𝜋/6 (B) Equilateral
(C) Isosceles, ∠C = 2𝜋/3 (D) Obtuse, ∠B = 𝜋/6
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