I think using trig formula cos x = A/H would be a lot simpler. Using the same triangle this would give cos 30 = 7/2 /r (where r is radius/hypotenuse). Rearranging gives r= 7/2/cos 30. Cos 30 is root 3/2 (see http://sciencepages.tripod.com/surd.html). Simply and QED. I found the whole ratios part a bit confusing.
Calc or non calc paper
How are we supposed to know the ratio of the triangles?!!!?!!!??!
if you do it with the sine rule you get 7 root 3 over 3
really hope this comes up tomorrow now
I don’t get where the 2, square root 3 came from ?
Did you make it up or found of somewhere. If you did find it can you send me the link please. Great video btw!
the maths paper was hard I reckon I got 50 out of 80 on the higher
What did you guys think about the non-calculator paper?
Can you go through 2018 paper 1
It is hard for me when I was at elementary. Thanks for teacher that help me a lot. I love to support your channel my friend.
I think using trig formula cos x = A/H would be a lot simpler. Using the same triangle this would give cos 30 = 7/2 /r (where r is radius/hypotenuse). Rearranging gives r= 7/2/cos 30. Cos 30 is root 3/2 (see http://sciencepages.tripod.com/surd.html). Simply and QED. I found the whole ratios part a bit confusing.