One should not miss this.
If in a cyclic quadrilateral ABCD, AB = 3, BC = 4, CD = 5, & DA =6, then find the radius of circle.
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R=area/Semiperimeter
Radius 4.63
√819/19 sorry this is diameter
Radius is half of this
3.287 plzz confirm
R=3.287 units
rc = 1/(4*A) * √ (ab+cd) * (ac+bd) * (ad+bc)
4×area of quad×R=rt(ab+cd)+(ac+bd)+(ad+bc)
Area of quad=√{(s-a)(s-b)(s-c)(s-d)}
Is it right?
1/2(√819/√19)
3.28
✓247/✓28…..Wrong or right???
(✓1729)/4✓10
3.287
3.287
Sir I am a new viewer of your channel. First time. I would like to know that are your videos helpful for SSC CGL also or just for CAT XAT etc. Please do reply Sir
3.287 by Bhramagupta's theorem
R=1/4sqrt(((ac+bd)(ad+bc)(ab+cd))/((s-a)(s-b)(s-c)(s-d))).
sir, is it possible to form a quadilateral with these values?
We can use Ptolemy theorem
AD*BC+BA*DC=(diameter)^2
Radius=√39/2
3.181cm
3.287
Root39/2
3.287
R=1/4rootasquare+bsquare+csquare+dsquare yehi formula hai na sir
3.20
R=4.636 ,R=√((a2+b2+c2+d2)/4)
(root (1729/10))/4 i mean 3.287
2.5
3.5 cm radius
√10.75
sir redius is = 4.5
2.5
3 root 10/2
3.12
3.60
Explain how
Thank u sir daily aise hee Lana question
Morning m question n evening m answer