Hello Guys…..In this video, our Mentor MKA Sir has explained inorganic mechanism and remaining two types of reaction viz. Oxidisers-reducers and complexing reaction, which are very helpful for IIT Jee Mains, Advance, BITSAT, NEET and AIIMS. Now, there is no need to mug-up these all reactions.
Consider a situation in which one halogen (chlorine, for example) is reacted with the ions of another (iodide, perhaps) from a salt solution. In the chlorine and iodide ion case, the reaction is as follows:
Cl2 + 2I- = Cl- + I2
The iodide ions lose electrons to form iodine molecules. In other words, they are oxidized.
The chlorine molecules gain electrons to form chloride ions— they are reduced.
This is therefore a redox reaction in which chlorine acts as an oxidizing agent.
In each case, a halogen higher in the group can oxidize the ions of one lower down. For example, chlorine can oxidize bromide ions to bromine:
The bromine forms an orange solution. As shown below, chlorine can also oxidize iodide ions to iodine:
The iodine appears either as a red solution if little chlorine is used, or as a dark gray precipitate if the chlorine is in excess.
Bromine can only oxidize iodide ions, and is not a strong enough oxidizing agent to convert chloride ions into chlorine. A red solution of iodine is formed (see the note above) until the bromine is in excess. Then a dark gray precipitate is formed.
Iodine won’t oxidize any of the other halide ions, except possibly the extremely radioactive and rare astatide ions.
Transition elements have tendency to form complexes more than s and p block elements, which form only a few complexes.
The reason is :-
They have small , highly charged ions.
They have vacant low energy orbitals to accept lone pairs of electrons donated by other groups or ligand .
So they are able to form complexes with the groups which are able to donate an electron pair . These groups are known as ligands.
Many other complex reactions from Complex has been discussed in details inside the lecture. We hope, it would be extremely helpful for your preparation.
Inorganic Reaction Mechanism (Part-2)
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