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Divisibility rules are efficient shortcut methods to check whether a given number is completely divisible by another number or not. These divisibility tests, though initially made only for the set of natural numbers (N), can be applied to the set of all integers (Z) as well if we just ignore the signs and employ our divisibility rules. Note that the term “complete divisibility” means that one of the numbers with the smaller magnitude must be a divisor of the one with the greater magnitude.

How we can solve problems from this topic in our competitive examination with short tricks. In this video, we will discuss all the things related to Divisibility Rules (Part of Number System Topic). In Competitive exams like SSC CGL, SSC CHSL, Bank PO, Bank Clerk, IBPS PO, IBPS Clerk, SBI PO, SBI Clerk, SSC CPO etc. there are some questions asked from this topic.

If you are thinking about ssc cgl maths preparation 2018, bank po/clerk preparation 2018 or any other exam preparation this topic helps you to improve your preparation.

Here’s what you’ll learn in this action-packed guide:

First, I’ll show you the right (and wrong way) to optimize your time. Use Short tricks, and it’s something I do almost every time I solved a question.

Divisibility by 1: Every number is divisible by 1.

Divisibility by 2: The number should have 0,2,4,6, or 8 as the units digit.

Divisibility by 3: The sum of digits of the number must be divisible by 3.

Divisibility by 4: The number formed by the tens and units digit of the number must be divisible by 4.

Divisibility by 5: The number should have 0 or 5 as the units digit.

Divisibility by 6: The number should be divisible by both 2 and 3.

Divisibility by 7: The absolute difference between twice the units digit and the number formed by the rest of the digits must be divisible by 7 (this process can be repeated for many times until we arrive at a sufficiently small number).

Divisibility by 8: The number formed by the hundreds, tens and units digit of the number must be divisible by 8.

Divisibility by 9: The sum of digits of the number must be divisible by 9.

Divisibility by 10: The number should have 0 as the units digit.

Divisibility by 11: The absolute difference between the sum of alternate pairs of digits must be divisible by 11.

Divisibility by 12: The number should be divisible by both 3 and 4.

Divisibility by 13: The sum of four times the units digits with the number formed by the rest of the digits must be divisible by 13 (this process can be repeated for many times until we arrive at a sufficiently small number).

Divisibility by 25: The number formed by the tens and units digit of the number must be divisible by 25.

Divisibility by 125: The number formed by the hundreds, tens and units digit of the number must be divisible by 125.

So finally, today we learned Successive division question with some good and short tricks. If you have any doubt regarding these question simply type in the comment box.

In our later video, we will discuss more questions and explained to you how it can be useful for your ssc cgl mains exam preparation 2018.

If you’re looking to get more actionable Maths videos like this one, make sure to subscribe to my YouTube channel right here:

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Carry on sir

गज़ब का ट्रिक सर…🙏🙏🙏

Excellent video sir

thanks for such a great effort for us sir..

sir 27 ki divisibility kya hai

Excellent sir jee

Plz upload more videos of Ix and xth class because I am too weak in mathematics sir jee means advanced mathematics cgl cds trigonometry algebra Cordinate Geometry number system menstruation Polynomials quadratic equation Real number statatitics. Trigonometry height and distance. Triangles lines and angles. And many more related to Advanced mathematics. Plz do not mind Sir jee

You are the best Sir

Though he looks like a typical 90's teacher but his teaching techniques are far better than those .and still better than today so called modern teacher

….

He is genuine teacher not those who say we are the number. The way of teaching is awesome. Sir. Keep it up. U are the only one who could understand weaker Student's problems.