Numerical-1 | current electricity | iit -jee-neet - Videos

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Plz watch this video till end cz one surprise is there for all f u☺

In this video i have explained some imp numerical based on jee and neet which is of from current electricity

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21 COMMENTS

  1. once again sir,….
    there is in question no. 11 …
    in current division metod the sum of resistance is 21……but HOW?
    I think those are in parallel combination so the sum is ….1/R=1/14+1/7=3/14 (i.e., R=14/3…..is already calculated as Requivalent)…..
    Thamk You

  2. sir you are grateful vidoes sir I am happy very excited next videos 😘😘😘😘😘😘😘😘😍😍😍😍😍😍😍😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😍😍😍😍😍😍😍😘😘😘😘😍😍😍😘😘😘😍😍😍😍.😁😉🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗. Thanks you, thanks you, thanks you and everyday watch this videos. finally thanks you😍😍🤗🤗

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