In a triangle ABC, AB = 7 cm, BC = 24 cm, CA = 25 cm. I is a incentre of this triangle then area of triangle ABI is__________
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10.5
Inradius = 7+24-25/2 = 3
Area of ABI = 1/2*7*3 = 10.5cm2
triangle ABI is 21/2=10.5 cm^2
10.5
10.5
(84×7)/56 =21/2=10.5cm^2
73.5
10.5
10.5
10.5
Area of traingle ABI =21/2=10.5
10.5
10.5 aa rha h sir
10.5
10.5
Sorry 10.5
10.5 square cm
10.5 square cm
10.5
incentre radius R=(p+b-h)/2
R=3
Area of triangle ABI=(AB× R)÷ 2
=( 7×3)÷2
=10.5
10.5
10.5 cm^2
1/2*3*7=10.5cmsquare
10.5
10.5cm square
10.5 inradius of a right angle triangle is AB+BC-CA/2 . SO IT IS 3. NOW, ABI 1/2×7×3=10.5
Inradius = ( 24 + 7 – 25 )/2 = 3
Area of triangle ABI = 1/2*3*7 = 10.5
10.5cm^2
Inradius = 3
Area of AIB = 10.5 cm^2
10.5 cm
Inradius=3.AIB=10.5cm^2
Either 36 or 10.5cm^2
10.5
10.5
10.5 😀
Mocks kb aayega sir phle inform kar dijiyega please
28cm
10.5
Sir Please do videos in English it would be helpful
10.5
7*3/2 = 10.5
Very easy as compared to ur other daily Qs
21/2
10.5
10.5
Sir aap online classes provide krte ho kya
21/2
10.5
10.5cm^2
(1/2)×(7×24)×(7/56)= 10.5