A rectangle is placed on the base of a triangle of area 40 sq. cm with base 8 units, such that two of its vertices are in the base and the other two vertices on the other two sides of the triangle. What is the maximum area of the rectangle?
=================================
To Join Online Classes for Quant (Maths) , DI , LR (Reasoning) for CAT / SSC / BAKING – https://www.3elearning.in/
To join off line classroom at Ranchi : visit – https://goo.gl/SaezYz
=================================
Learning Anytime Anywhere.
Free and best youtube learning platform, for CAT/ XAT /SNAP/ CMAT/ SSC / BANKING/ Maths By Amiya
=================================
For more JOIN FB GROUP – https://www.facebook.com/groups/MBAMathsByAmiya/
LIKE – https://www.facebook.com/MathsByAmiya
Telegram Channel : https://t.me/mathsbyamiya
To Join Telegram Group: https://t.me/joinchat/F_j9Dw9Mgi6Je4JSoUd9AQ
Website: www.3elearning.in
Best Maths Questions, Best Maths Questions for CAT, CLAT, SSC, UPSC, BANKING, PO, SBI, SNAP, IIFT, XAT, SSC CGL
source
20
20
20
20cms..max area would be half of the bigger triangle..
1600/81
20
20cm^2
20
1600/81
1600/81.
1600/81
1600/81
20
1/2×8×x=40
X=10
Area=10×8=80
20
The function for rectangle is 4/5(10-h)×h when we diffrenciate and take it equal to zero we got H=5 then area of rectangle become 20
20
1600/169
Length of rectangles being x,y. From similarity 5x +4y =40
GM^2 <= AM^2
(5x * 4y) <= {(5x+4y)/2}^2
Or, 20 xy <= 20^2
Or, xy <= 20
Ans = max area of rectangle possible is 20 sq unit
And it can also be proved that for any triangle, Area of the rectangle placed according to the questions inside the triangle will have maximum area as half of the area of the triangle.
20 cm^2
1600/81
1600/81
1600/81 concept in video
https://youtu.be/MwBnGlVb9OA
Sir kal Aapko ek question mail kiya tha plz uska solution bta digiye …
1600/81
Answer : 20 sq. cm
Ans is 20…. BH/4
20
1600/81
20cm^2
20
20
20
1600/81