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first two question 20 minutes … this is not good right now
Thank you sir….very fruitful session was…
continue Di class
Day by day I am falling in love with your maths questions. Plz bring more questions like this.
And another thing, in xy +42 = 6x + 7y, if y becomes 6 then value of x can be any positive or negative integer. So, I think the answer will be CND.
get to know so many new concepts.. thank you sir🙏👍👍👍👍
No relationship
Nice Session Sir…….thanks…….
Sorry sir .
Video tho ache h sir mgr speed bhut slow h apki b …thoda active Rha kro session main like sumit sir
yar i only get sumit sir's method 🙁 meko ni aaya ye wala 🙁
Thank u sir 🙂
NYC plz continue sir
Sumi sir best hai
Bank class only sumit sir
Always hv something new in ur sessions .. thank you sir
sir i like your class….u r take different question…..
sir i like your class….u r take different question…..
sir your videos are very good….thank u
thanks sir
Sir the way u speak is really funny n interesting so every session becomes interesting ..n ur way of teaching is really hatke…now every concept about inequality cleared..tysm sir
for xy+42=6x+7y … there can be solution of x=0,y=6 or y=0,x=7…. In this case ,answer should be no relation
Thanks sir
You are the best Sir
Bahut badhiya
Sir
Thank u sir for providing the question like…
2x+3√x+21=0
2y-15√y+28=0
Because without solving the question I thought answer would be y>x…But now I understand completely…..
sir vo x^2 kaise aa gaya….x^10/7 is question me..plz help me
Nice questions
Sir poora mention toh kiya kro ki kaise aaya
Aap direct x2 bna dete ho
Please sir define clearly all the calulations
thanks a lot sir
Thanq sir…awasom concept
xy+42=6x+7y me value put karenge to bhut sare value nikal sakte h for example x=0&y=6,or y=0,&x=7
thanks fr dis class sir , really thanks a lot
yes sir DI is most important topic.plz sir take regular class of DI
than you sir khup chhan question ….
sir samajh ni aaraha hi
sir next class kab h?
Sir in your session I learn a lot of new concepts.so thanks a lot and bring more lectures like this