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Awesome
4
4 on 4, thanks sir!
2 thank you sir!!
thanks u r great
3/4 just silly mistake
Plz comment if we take initial relation between x1 and x2 and then differentiate to get relation b/w v and then again differentiate
the net relation obtained would be very Bad
Sir, x1cos(theta) = x2 now if differentiate it then it would lead to that complex relation. It is because here we are not assuming theta constant. When we write a1cos(theta) = a2 then it is valid only at a particular angle theta. It is not a general relation between accelerations of two blocks….. Right ?
congrats vk sir…1 million views?✌
sir theta is continuously changing so how come can we write nd use the expression of summation T*V =0 nd not write the same for acceleration, I mean it wud be gre8 if u wud throw light on that portion well
Sir , if we write V1 = V2 sec thita, instead of as u said and then differentiate we get a different relation , now which one is correct?
4 on 4.
Thank you, Sir.
2 marks….hahahhaha
sir thank for explaining us all videos. my all friends watch your videos and like it
but sir our we also rotational motion chapter videos as soon as possible.
thanks again
how i get d∅/dt
2 thank u sir
2