26. There are four friends A, B, C and D. Initially all have some quantity of pure milk. If A gives his 1/10th quantity of the milk to B, then B gives his 1/10th current quantity of the milk to C, then C gives his 1/10th current quantity of the milk to D and at last then D gives his 1/10th current quantity of the milk to A, and now all have equal amount of milk. Then find the % change of quantity of mild with A now wrt to A was initially.

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1.26 % increase

It increased 1.35%

Considering final. Milk in all to be

9 9 9 9

Now moving backwards

We get initial quantity as

8.88 9.12 9 9

So the milk with a has become from 8.88 to 9

That's increase of 1.35%

1.25 %

a=8. b=8.2 c=8.1 d= 8.1. after changing a bacomes. 8.1. change is 10/8% which is 1.25 %. i hope it helps.

1.25%decrease

Let all have 9 ltr… By reverse ratio we'll get A has initially 80/9ltr

So %change

=[(9—80/9)/80/9]×100=1.25% increase

+1.25%

1.25% increase!!

1.25% increase

increase1.25%

1.25% increase

1.25% increase

+1.25 %

I got 8.4

1.25% inc

yes its 1.25% increase.

1.25 % increase

1.25% increases

1.25% increase

1.25% increase

1.11% increase

lets assume all have final amt left is 1:1:1:1,,, now backward calculation karne pe to A ka initial value 16105/14641 aa rha hai and final value to 1 hai hi….if my process is wrong then pls correct me amiya sir or any 1….

(9-80/9)/(80/9) * 100 = 1.25

1.25% increase

Equal amunt 9:9:9:9 let kar lengy fir reverse condition aply karengy

Then a ka initial 80/9 nikle

Increase=9-80/9=1/9

%={(1/9)÷80/9 }× 100=1.25

0%

8.9%decrease

1.25% increase

1.25% inc

1.25 %

1.25% increase

Make final amount of all ABCD 100ml .consider only milk of A and D .U Will get initial amount of A as well as% increase.

lage raho sab ..apne brain ko beautiful sabit krne me….agr sach me hai to provide with detailed answer

10.8 percent sir i assumed 40000 lit of milk to every one then find and lastly finded the aver of all the then foune the change

0% change

1.25%^