26. There are four friends A, B, C and D. Initially all have some quantity of pure milk. If A gives his 1/10th quantity of the milk to B, then B gives his 1/10th current quantity of the milk to C, then C gives his 1/10th current quantity of the milk to D and at last then D gives his 1/10th current quantity of the milk to A, and now all have equal amount of milk. Then find the % change of quantity of mild with A now wrt to A was initially.
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1.26 % increase
It increased 1.35%
Considering final. Milk in all to be
9 9 9 9
Now moving backwards
We get initial quantity as
8.88 9.12 9 9
So the milk with a has become from 8.88 to 9
That's increase of 1.35%
1.25 %
a=8. b=8.2 c=8.1 d= 8.1. after changing a bacomes. 8.1. change is 10/8% which is 1.25 %. i hope it helps.
1.25%decrease
Let all have 9 ltr… By reverse ratio we'll get A has initially 80/9ltr
So %change
=[(9—80/9)/80/9]×100=1.25% increase
+1.25%
1.25% increase!!
1.25% increase
increase1.25%
1.25% increase
1.25% increase
+1.25 %
I got 8.4
1.25% inc
yes its 1.25% increase.
1.25 % increase
1.25% increases
1.25% increase
1.25% increase
1.11% increase
lets assume all have final amt left is 1:1:1:1,,, now backward calculation karne pe to A ka initial value 16105/14641 aa rha hai and final value to 1 hai hi….if my process is wrong then pls correct me amiya sir or any 1….
(9-80/9)/(80/9) * 100 = 1.25
1.25% increase
Equal amunt 9:9:9:9 let kar lengy fir reverse condition aply karengy
Then a ka initial 80/9 nikle
Increase=9-80/9=1/9
%={(1/9)÷80/9 }× 100=1.25
0%
8.9%decrease
1.25% increase
1.25% inc
1.25 %
1.25% increase
Make final amount of all ABCD 100ml .consider only milk of A and D .U Will get initial amount of A as well as% increase.
lage raho sab ..apne brain ko beautiful sabit krne me….agr sach me hai to provide with detailed answer
10.8 percent sir i assumed 40000 lit of milk to every one then find and lastly finded the aver of all the then foune the change
0% change
1.25%^