FIND THE AREA OF SHADED REGION
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24.5π
24.5pi
24.5π,, half of area of circle
24.5 pi
77
Samjh nhi aa rha h 😬😂😂
I think here size of semicircles doesn't matter as long as both are touching each other. So Make 2 semicircles of equal radius touching each other at the center of bigger circle.. we can draw an isosceles right angle triangle in each semi circle with sides 7,7,7√2. And the radius of semi circles will be 7√2/2=7/√2. Total shaded area will be the area of a complete circle with radius 7/√2 i.e 24.5π
49pi/2
77
By solving the equation sum of radius of 2 inner semi circle comes zero which is not possible ,when we assume radius at any point other than the touching point equation does not satisfy So we have to take that touching point as radius of bigger circle then radius of both circle become equal and hence area is 49π/2
If diameter is not perpendicular to the chord then we can solve it or not? If yes then plzz explain how to solve it thnk u
77 unit square.
I assumed both semicircle as equal so I got the radius of the semicircle is 【7/√2】 so area of both semicircle is π(7/√2)^2 unit square.
Pi49/2
49 pie/2
I had asked you 3 questions, but still now you can't answer it
77
24.5pi
77
Area of shaded region is equal to area of circle/2
=77
24.0528 units
19.80* pai(approx)
Ye toh Unacademy ka logo h
15.3125
24.5pi
77