VIDEO COURSE AVAILABLE IN DVD OR PEN DRIVE
FOR INFORMATION
CALL +91-8115100372
VISIT OUR WEBSITE
www.radixvideoclass.com
source
VIDEO COURSE AVAILABLE IN DVD OR PEN DRIVE
FOR INFORMATION
CALL +91-8115100372
VISIT OUR WEBSITE
www.radixvideoclass.com
source
Copyright ©2024 EduGorilla Community Pvt. Ltd.
it was an easy question….
Thanks sir
sir in the first question you proved tri ABD & tri ACD by SAS congruent but if you look the angle is not included between two sides , in SAS congruency angle must come in between two sides for two triangles to be SAS congruent
let me write correct solution
tri ABD is similar to tri AEC
angle BAD=angle EAC (AD is the bisector of angle A)
angle AEC=angle ABC (angle subtended by same chord on circumference)
so
AB/AE=AD/AC
AB*AC=AD*AE ……….(1)
to find AB.AC+AE.DE = AB.AC + AE(AE-AD)= AB.AC + AE^2 – AE.AD
from (1) AB.AC=AE.AD
so AB.AC+AE.DE = AE^2
I will refer to a simple solution for you guys….First of all read the question carefully, it's not mentioned anywhere that the triangle is of which type that means this particular case must be true for all kind of triangles. Therefore i will consider that the triangle is equilateral triangle and try to solve with supposition of a numerical value for sides and all the angles inside the triangle will be 60 degree each(as i have considered that the triangle is equilateral). and after that i think you all will be certainly able to solve this question …Right. comment please if you got my concept….
RADIX ONLINE NO 1 SSC EXAM S