GEOMETRY QUESTION FOR CAT, SSC, CDS AND OTHER COMPITITIVE EXAMINATION - Videos

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5 COMMENTS

  1. sir in the first question you proved tri ABD & tri ACD by SAS congruent but if you look the angle is not included between two sides , in SAS congruency angle must come in between two sides for two triangles to be SAS congruent

    let me write correct solution

    tri ABD is similar to tri AEC

    angle BAD=angle EAC (AD is the bisector of angle A)
    angle AEC=angle ABC (angle subtended by same chord on circumference)
    so
    AB/AE=AD/AC
    AB*AC=AD*AE ……….(1)

    to find AB.AC+AE.DE = AB.AC + AE(AE-AD)= AB.AC + AE^2 – AE.AD

    from (1) AB.AC=AE.AD

    so AB.AC+AE.DE = AE^2

  2. I will refer to a simple solution for you guys….First of all read the question carefully, it's not mentioned anywhere that the triangle is of which type that means this particular case must be true for all kind of triangles. Therefore i will consider that the triangle is equilateral triangle and try to solve with supposition of a numerical value for sides and all the angles inside the triangle will be 60 degree each(as i have considered that the triangle is equilateral). and after that i think you all will be certainly able to solve this question …Right. comment please if you got my concept….

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