A SQUARE is placed on the base of a triangle of area 40 sq. cm with base 8 units, such that two of its vertices are in the base and the other two vertices on the other two sides of the triangle. What is the maximum area of the SQUARE?
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1600/81
1600/81cm2
base×height/base + height = side of square .ans 1600/81
1600/81
1600/81 cm^2
1600/81
1600/81
1600/81
maximum =a.b/a+b than square its formula
1600/81
16 square unit
1600/81
1600/81
1600/81
1600/81
, 1600/81.
20 sq unit
1600/81
10-10x=8x
X=5/9
side=10-10*5/9=40/9
area=1600/81
25😉
1/x= 1/b+1/h= 1600/81
1600/81
1600/81
1600/81
1600/81
1600/81
1600/81
1600/81
Side of square=(B×H)/(B+H)
Area of square=1600/81
19.75 sq unit
1600/81
1600/81
Questions ko Hindi mai v speech kre plzzz sir.
I think We can also use trignometry to find the maximum area…answer will be same 1600/81
20.25
1600/81
1600/81