Q. Find the total number of terms in the expansion of (?+?+?^?+?^? )^??
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31
70 terms
31.max power 30 min power 0…
286 terms
286
31
21
(𝟏+𝒙+𝒙^𝟐+𝒙^𝟑 )^𝟏𝟎 : power of x lies from 0 to 30 so there will be 31 terms
31
31
286. as (10+4-1)!/10!*3!=13!/10!3!=11*12*13/3*2=286 that is ans
31 terms
31
In the expansion, highest and lowest powers of x will be 30 and 0 respectively.
And since it has continuous powers of x (0,1,2,….30), the expansion will have all the powers of x ranging from 0 to 30.
Therefore, the no. of terms in the expansion will be 31.
121
31 terms, if all the terms in multinomial had been distinct, the expansion would hv given 286 terms.
31 terms
286
286
11
31
286
286
please see this question your video: https://youtu.be/7yq4eI1hy2Y?t=2h37m7s
here 42 is not coprime to 20. and you applied Cyclicity.
see another question in next video: https://youtu.be/LTa-enrINh8?t=1h5m57s
here 22 is not coprime to 10. and you applied CRT.
Please please please elaborate these two as I see in your live classes noone noticed this!!
you didn't reply earlier comment!
31