XAT 2018 Quant Solutions Analysis : Maths By Amiya - Videos

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XAT 2018 Quant Solutions Analysis : Maths By Amiya
48. 10 + 10^3+ 10^6 + 10^9
49. A,B, C and D can complete a piece of work in 10,12,15 and 18 days respectively. Any one can either work or wont wok on any day. If after 3rd days 50% of the work is completed then among the options which could be working pattern of them.
50. If ratio of diagonals of a rhombus is 3:4 and length of side is 15 cm, then area of the rhombus is ________
51. If a quantity P first increased by x% then decreased by y% then it again becomes P and difference of magnitude of x and y is y only then value of x is
52. A mixture consists of three liquids , water , A and B. If water is 1/3rd of total volume of mixture, and ratio of A and B in the mixture is 5:3. If all water is removed by a membrane, but in this process some part of liquid A is also removed, and in this process total 200ml (water+A) is removed and in the rest of mixture ratio of A:B is 7:9 then find quantity of water in initial mixture.
53. A coin of radius 3cm is dropped on a square floor, which has square tiles of side 10cm then what is the probability that coin falls inside the tile.
54. If it required 2lit of paint to paint a sphere then how much lit of paint is required to paint 4 equal parts of this sphere.
55. A persons covers a distance with V_1 speed in 30 min. If he first cover the same distance with V_1 speed for 10 min then takes 5 min rest then moves with V_2 speed for another 30 min then covers the remaining distance. Then what is the ratio of V_2 to average speed of next journey (including the rest)
56. A pole of height 300m makes an angle of 30° on point A which is north to the pole and 45° on point B, which is in the east of the pole. Then shortest distance between A and B is _______
57. Two quadratic equation has a common roots, and three roots are A, B and C which are natural number. If A+B+C = 41 and product of roots of an equation is 35 then
58. There are 8 clocks and there timings follow a mathematical pattern. Seven timings are given below find the 8th timing.; 1:55; 2:03; 2:11; 2:24; 2:45; 3:19 and 4:14
59. In a class number of boys are 30 more than girls. If some more girls join then ratio of boys to girls becomes 3:5, then minimum number of girls who joined is ___
60. If a man travels A to B with V1 speed in T min and then B to C with V2 speed in T min, angle of AB and BC is 105°, then he travels C to A with V2 speed, and angle of CA and AB is 30. then find the time to cover CA distance in terms for T.
61. In a college there were 4 subjects. 1 compulsory and rest 3 are electives. All students must have to take the compulsory paper and 2 electives out of three. If 45, 55 and 70 are number of students who took three subjects. The minimum number of students who choose any subject could be ___
62. If unit digit of 408X^63 and 789Y^85 are same , where X and Y are different digits then X+Y could be
63. Number of negative integral solution of 2≤|x-1|*|y+3|≤5 is
64. A man has tendency to expend Rs x on x day of month. (e.g. on 5th of any month his expense is Rs 5) if sum of last four days is in the form of 2^N , then value(s) of N could be
65. There is a cone of base radius 4 cm and slant height of 12cm. If is is cut by a plane parallel to its base so that ratio of curve surface of smaller cone to remaining frustum is 1:2, then slant height of frustum is______
66. There are two circle of radii 2 cm and √2cm, cut each other at points A and B. if centers of both circle lie in the same side of line AB then area of common part shared by both circles is ______ (if AOB = 60° , O is center of bigger circle.

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15 COMMENTS

  1. Q61 should be 40 I guess which was in the options. 70 total students. Each will choose 2 electives. Do total in electives should be 140. 45+55=100. Therefore rest 40 in 3rd Elective.

  2. In question 52.A coin of radius 3cm is dropped on a square floor, which has square tiles of side 10cm then what is the probability that coin falls inside the tile
    You can then shade the area of a grid square where the coin center cannot fall — this shaded area will look the same in every square. If the coin radius is rr and the grid square sides have length dd, there's a small square of side length d−2rd−2r in each square where the center can fall without the coin extending beyond the grid square.

    So the probablity of staying within the square becomes
    (d−2r)sq /d sq = (10-6)sq/10 sq = 0.16 and not 0.36

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